tolong di jawab kak 1) lim x mendekati 1 = 1-√x/ 1-x^2. 2) lim x mendekati 2 = x^2-5x+6/ x^2-4.
Matematika
stmunaaprilia
Pertanyaan
tolong di jawab kak
1) lim x mendekati 1 = 1-√x/ 1-x^2.
2) lim x mendekati 2 = x^2-5x+6/ x^2-4.
1) lim x mendekati 1 = 1-√x/ 1-x^2.
2) lim x mendekati 2 = x^2-5x+6/ x^2-4.
1 Jawaban
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1. Jawaban saruendut
1) lim x-1 = 1-√x/1-x²=1-x²/1-x²
=1-1²/1-1²=0
2) lim x-2=x²-5x+6/x²-4
=(x-6)(x+1)/(x-2)(x+2)
=-12/0=0