Matematika

Pertanyaan

dik. g(x+1)=2x-1 dan f(g(x+1))=2x+4. maka nilai f(0)

2 Jawaban

  • g(x+1)=2x-1
    f(g(x+1))=2x+4
    dimasukan
    f(g(x+1))=2( 2x-1 )+4
    =4x-2+4
    =4x+2
    f(0)= 4x+2
    4(0)+2
    2
  • g(x - 1) = 2x - 1
    f(g(x + 1)) = 2x + 4
    f(2x - 1) = 2x - 1 + 5
    f(2x - 1) = (2x - 1) + 5
    f(x) = x + 5
    f(0) = 0 + 5 = 5

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