PQRS adlah jajargenjang,dngn pnjang TR=22 CM, PQ=7 CM, dan QR=25 CM.maka pnjng PT adlah...?? Tolong bntu ya...!!
Matematika
Adtrhyndha
Pertanyaan
PQRS adlah jajargenjang,dngn pnjang TR=22 CM, PQ=7 CM, dan QR=25 CM.maka pnjng PT adlah...??
Tolong bntu ya...!!
Tolong bntu ya...!!
1 Jawaban
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1. Jawaban REYKAL
SR = PQ
QR = SP
TR = TS + SR
TS = TR-SR
TS = 22 - 7
TS = 15 cm
Hipotenusa = SP = QR = 25 cm
(Phytagoras)
SP² = TS² + PT²
PT² = SP² - TS²
PT² = 25² - 15²
PT² = 625 - 225
PT = √400
PT = 20 cm
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