diketahui barisan geometri dengan U3=4 dan U5=16. suku ke 10 barisan tersebut adalah??

U3 = 4
U5 = 16
r² = 16/4
r² = 4
r = √4 = 2

U3 = a.r^n-¹
4 = a.2^3-¹
4 = a.2^2
4 = a.4
a = 4/4 = 1

U10 = a.r^n-¹
U10 = 1.2^10-¹
U10 =1.2^9
U10 = 512

U 5 = ar^4 = 16
U3 = ar^2 = 4
r^4-2 = 16/4
r^2 = 4
r = akar dari 4
r = 2
Cari a
U3 = ar^2 = 4
a(2)^2 = 4
a (4) = 4
a= 4/4
a = 1
Cari u10
u10 = ar^9
= 1 (2)^9
= 1 (512)
= 512