sebanyak 20 ml ba(oh)2 0,25M dicampur dengan 30ml ch3cooh 0,5M (ka 10*-5) maka ph campuran adalah

20 mL Ba(OH)2 0,25 M + 30 mL CH3COOH 0,5 M
Ka = 10^-5

pH campuran ... ?

n Ba(OH)2 = M × V
n Ba(OH)2 = 0,25 × 20 mL
n Ba(OH)2 = 5 mmol

n CH3COOH = M × V
n CH3COOH = 0,5 × 30 mL
n CH3COOH = 15 mmol

#Reaksi
... Ba(OH)2 + 2 CH3COOH => Ba(CH3COO)2 + 2 H2O
M : .... 5 ................. 15
R : ..... 5 ................. 10
___________________---
S : .... --- .................. 5 ...................... 5 ................... 10

[H^+] = Ka × Asam lemah/Basa konjugasi
[H^+] = 10^-5 × 5/5
[H^+] = 10^-5

pH = - log [H^+]
pH = - log 10^-5
pH = 5