Hasil dari ∫x√(4x+1) dx =

u = 4x + 1 → du = 4 dx
dx = (1/4) du
= int x√u du
dari → u = 4x + 1
4x = u - 1
x = (1/4)(u - 1)
= (1/4) int (u - 1)√u du
= (1/4) int (u^(3/2) - u^(1/2)) du
= (1/4)[(2/5)u^(5/2) - (2/3)u^(3/2)] + c
= (1/4)[(2/5)√(4x + 1)^5 - (2/3)√(4x + 1)³] + c
tinggal sederhanakan sesuai yg diminta