tolong jawab ya plisssss no 2 dan 3

Sudut

2) <AOD  : <DOC = 3 : 5
misal <AOD = 3a dan <DOC  = 5a
<AOD + <DOC +<BOC = 180 (pelurus)
3a + 5a + 60 = 180
8a = 180- 60
8a = 120
a = 15
<AOD = 3a= 3(15) = 45°
<DOC = 5a = 5(15)= 75°

3)
a. 3/5 sudut penyiku = 3/5 x 90= 54°
b. 5/6 sudut lurus = 5/6 x 180 = 150°
c. 11/12 sudut putaran penuh= 11/12 x 360 = 330°