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ph 3,7 gram kalsium hidroksida dalam 10 liter air

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  • 3,7 gram Ca(OH)2
    V = 10 L = 10000 mL
    Mr Ca(OH)2 = 74

    pH ... ?

    *Molaritas Ca(OH)2
    M = gram/Mr × 1000/mL
    M = 3,7/74 × 1000/10000
    M = 0,05 × 0,1
    M = 0,005

    *Ca(OH)2 adalah basa kuat
    [OH^-] = b × Mb
    [OH^-] = 2 × 0,005
    [OH^-] = 0,01
    [OH^-] = 10^-2

    pOH = - log [OH^-]
    pOH = - log 10^-2
    pOH = 2

    pH = 14 - pOH
    pH = 14 - 2
    pH = 12

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