nilai dari cos105°-sin15°/cos75°-cos15° adalah

Melalui aturan sudut berelasi, didapat :
cos105° = cos (90 + 15)° ⇒ cos105° = -(sin15°)
sin15°
cos75° = cos (90 - 15)° ⇒ cos75° = sin15°
cos15°

sin15°-(sin15°÷sin15°) - cos15° = 
-[tex](- \frac{1}{4}( -\sqrt{6} + \sqrt{2} ) ) - 1 - ( \frac{1}{4} ( \sqrt{6} + \sqrt{2} )) \\ \frac{1}{4} \sqrt{6} - \frac{1}{4} \sqrt{2} - 1 - \frac{1}{4} \sqrt{6} - \frac{1}{4} \sqrt{2} \\ \frac{1}{2} \sqrt{2} - 1[/tex]

Maap kalo salahh