persamaan garis lurus yang melalui titik (3,-4) dan sejajar dengan garis 2x - 5y - 10 =0 adalah... a.2x + 5y =-14 b.5x + 2y =7 c.2x - 5y =26 d.5x - 2y =23

titik (3,-4)
2x-5y-10 = 0
m = -a/b = -2/-5 = 2/5

syarat sejajar ⇒m₁=m₂

persamaan garis lurusnya
y-y₁ = m(x-x₁)
y-(-4) = 2/5(x-3)
y+4 = 2/5(x-3)
5(y+4) = 5[2/5(x-3)]
5y+20 = 2(x-3)
5y+20 = 2x-6
-2x+5y = -6-20
-2x+5y = -26
2x-5y = 26

Jawabannya (C)