Matematika

Pertanyaan

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1 Jawaban

  • a.
    → Luas layang² = 1/2 x d1 x d2
    48cm² = 1/2 x 8cm x QS
    48cm² = 4cm x QS
    QS = 48cm² / 4cm
    QS = 12cm

    b.
    QO = QS - SO
    QO = 12cm - 5cm
    QO = 7cm

    PO = 1/2 PR
    PO = 1/2 . 8
    PO = 4

    PQ = √7² + 4²
    PQ = √49 + 16
    PQ = √65

    PS = √PO² + SO²
    PS = √4² + 5²
    PS = √16 + 25
    PS = √41

    c.
    L = a x t / 2
    L = 7cm x 4cm / 2
    L = 28cm² / 2
    L = 14cm