Tolong pakai cara ya! Terima kasih Jika ^7 log 2 = a dan ^2 log 3 = b, hitunglah ^98 log 6 = ?

²log 6 / ²log 98
= ²log (3×2) / ²log (7²×2)
= ²log 3 + ²log 2 / ²log 7² + ²log 2
= b + 1 / (2/a) + 1
------------------------ a
= (ba+a) / (2+a)
= a(b+1) / (2+a)