hitunglah vrms atom helium masanya 6,65 × 10^-27 kg a)suhu T : - 268°c b)suhu T : -260 °c c) suhu T : 25 °k

Vrms = √(3kT/m)

T = -268°C = 5 K

Vrms = √(3.1,38.10^-23.5/(6,65.10^-27))
= √(20,7.10^-23/(6,65.10^-27))
= √(20,7.10⁴/6,65)
= √(3,11.10⁴)
= 1,76.10² m/s

T = -260°C = 13 K

Vrms = √(3.1,38.10^-23.13/(6,65.10^-27))
= √(53,82.10^-23/(6,65.10^-27))
= √(53,82.10⁴/6,65)
= √(8,09.10⁴)
= 2,84.10² m/s

T = 25 K

Vrms = √(3.1,38.10^-23.25/(6,65.10^-27))
= √(103,5.10^-23/(6,65.10^-27))
= √(103,5.10⁴/6,65)
= √(15,56.10⁴)
= 3,94.10² m/s