bayangan y = 3x + 8 setelah digeser oleh matriks ( -2 1)

y=3x+8
3x-y+8=0

(x') = (x-a)
(y') (y-b)

(x')= (x+2)...... x=x'-2
(y') (y-1)..........y=y'+1
lalu substitusi
3 (x'-2) -(y'+1)+8=0
3x-6-y-1+8=0
3x-y+1=0...

Translasi

(x,y) + T(a,b) --> (x1. y1)
x1 = x + a  ---> x = x1 - a
y1 = y + b  --> y = y1 - b

y = 3x + 8  di T (-2,1)
(y1 -1) = 3(x1+2)  + 8
y - 1 = 3x + 6 + 8
y = 3x + 15