tentukan nilan n dari (n+3)! = n!

langsung aja y

(n+3)(n+2)(n+1)n! = n!

(n²+5n+6)(n+1) = 0

(n³+n²+5n²+5n+6n+6) = 0

n³ + 6n² + 11n + 6 = 0

n³ + 6n² + 11n = -6 ← jawaban

mungkin (n+3)! = (n+1)!

maka
(n+3)(n+2)(n+1)! = (n+1)!

(n+3)(n+2) = 0

n= -3 dan n = -2

semoga berguna +_+