The tangent line to the curve y = (x − 1)2 at the point (−1, 4) has equation 4x + y = 0. Thus, the value of the limit lim x→−1 x2 − 2x − 3 x + 1 is _______.
Matematika
Fendyseven07
Pertanyaan
The tangent line to the curve y = (x − 1)2 at the point
(−1, 4) has equation 4x + y = 0. Thus, the value of the
limit
lim
x→−1
x2 − 2x − 3
x + 1
is _______.
(−1, 4) has equation 4x + y = 0. Thus, the value of the
limit
lim
x→−1
x2 − 2x − 3
x + 1
is _______.
1 Jawaban
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1. Jawaban DB45
Limit bentuk 0/0
lim(x->-1) (x² - 2x -3)/(x + 1)
lim(x-> -1) (x+1)(x -3)/(x +1)
lim(x->-1) ( x -3)
x = - 1 --> limit = (-1 - 3)= -4