Matematika

Pertanyaan

2log 7+ 2log 96 - 2 log 8 - 2log42 =

1 Jawaban

  • ²log7 + ²log96 - ²log8 - ²log42
    =²log(7 · 96) - ²log(8/42)
    =²log672 - ²log4/21
    =²log(672/ 4/21)
    =²log(672 · 21/4)
    =²log3528

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