tolong dong plis tolongin

²log 96 + ²log 256^3/4 - ²log 64^2/3 - ²log 6
= ²log 96 + ²log (2^8)^3/4 - ²log (2^6)^2/3 - ²log 6
= ²log 96 + ²log 2^6 - ²log 2^4 - ²log 6
= ²log (96 × 2^6 ÷ 2^4 ÷ 6)
= ²log (96 ÷ 6 × 2^6 ÷ 2^4)
= ²log (16 × 2^2)
= ²log (2^4 × 2^2)
= ²log 2^6
= 6

Kalo menurut saya caranya begitu, ^aloga = 1 jadi jawabannya 7