a. 2log8 + 2log9 – 2log288 = .... b. 5log√27 . 9log125 + 16log32 = ... c. 10log250 + 10log16 – 10log41 = ....

A. 2log8 + 2log9 – 2log288 = 
²log8*9/288=
²log1/4=
-2
b. 5log√27 . 9log125 + 16log32 =
3²log5³.5log3^{1/3}+2⁴log2⁵=
3(3²log5)(5log3^{1/3})+5/4=
3(3²log3^{1/3}+5/4=
3(1/6)+5/4=
1/2+5/4=
7/4=1 3/4
c. 10log250 + 10log16 – 10log41 = (mungkin yang dimaksud 10log40? karena kalo 10log41 angkanya jelek sekali)
10log10+10log25.16/41=
1+10log9,75
Jika maksud 10log41 adalah 10log40 maka
10log250 + 10log16 – 10log40 =
10log10+10log25+10log16-10log4-10log10=
1+10log25.16/4-1=
10log100=
2
maaf kalau salah, semoga membantu