Diketahui luas belahketupat ABCD = 216 cm².jika panjang diagonal AC= 18cm,keliling belahketupat ABC =

Diketahui :
luas = 216 cm3
diagonal 1 (AC) = 18 cm
diagonal 2 (BD) ???

luas = 1/2 × d1 × d2
216 = 1/2 × 18 × d2
216 = 9 × d2
d2 = 216 : 9
d2 = 24 cm

AO = 1/2 × AC = 1/2 × 18 = 9
BO = 1/2 × BD = 1/2 × 24 = 12
AB=BC=CD=DA = (12×12) + (9×9)
= 144 + 81
= 225 (diakar 2)
= 15 cm
kll = AB + BC + CD + DA
= 15 + 15 + 15 + 15
= 60 cm

dik : L = 216 cm²
D1= 18 cm
dit : keliling ABC
Jwb :
L =1/2.D1.D2
216 = 1/2.18.D2
216 =9.D2
D2 = 216/9 = 24 cm
Panjang sisi belah ketupat
=√9² + 12²
=√81 + 144
=√225
=15 cm

keliling belah ketupat
K = 4s
=4(15)
=60 cm

Maaf kalo salah