diketahui barisan geomertri dgn U1 = x pangkat 3/4 dan U4 = x akar x.rasio barisan geometri tersebut adalah....

a = x^(3/4) dan U4 = x√x
Un = ar^(n-1)
x√x = [x^(3/4)]r³
r³ = (x√x)/x^(3/4) = x^(3/2) / x^(3/4)
r³ = x^(3/4)
r = [x^(3/4)]^(1/3)
r = x^(3/12) = x^(1/4)

U1 = ar^(1-1) = x^(3/4)
U1 = ar^(0) = x^(3/4)
U1 = a = x^(3/4)

U4 = ar^(4-1) = x√x
U4 = ar^(3) = x × x^(1/2)
U4 = ar³ = x^(3/2)

ar³ = x^(3/2)
x^(3/4) × r³ = x^(3/2)
r³ = x^(3/2) ÷ x^(3/4)
r³ = x^(3/2-3/4)
r³ = x^(6/4-3/4)
r³ = x^(3/4)
r = akar pangkat tiga dari x^(3/4)
r = x^(3/4×1/3)
r = x^(1/4)

Jadi, rasionya x^(1/4)