Soal integral, ada yang tau? No. 7, 8, 10. Tolonggg ;;w;;

No.10 Jawabannya A.
Caranya silahkan disimak dilampiran.

7.
∫ (1 - x² + 5x⁴) dx = Ax - B/3 x³ + x⁵ + c
x - 1/3 x³ + x⁵ + c = Ax - B/3 x³ + x⁵ + c
A = 1 , B = 1
(A - B)² = (1 -1)² = 0

8.
∫ (2x³ + x²)/(x²) dx = ∫(2x + 1) dx = x² + x +c  =  Ax² - Bx + c
A= 1 , B = - 1
(A+B)² = (1 - 1)² =  0