tentukan hp dari (rumus abc) 1.) 3x²-12=0 2.) 4x²+8=6x tolong kak thx
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Pertanyaan
tentukan hp dari (rumus abc)
1.) 3x²-12=0
2.) 4x²+8=6x
tolong kak thx
1.) 3x²-12=0
2.) 4x²+8=6x
tolong kak thx
1 Jawaban
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1. Jawaban 4LL
langsung aja y
1. 3x² - 12 = 0
a = 3
b = 0
c = -12
X1,2 = -b ± √b² - 4ac / 2a
X1,2 = -0 ± √0² - 4.3.(-12) / 2.3
X1,2 = 0 ± √0 + 144 / 6
X1,2 = 0 ± √144 / 6
X1 = 0+√144 / 6 = 12/6 = 2
X2 = 0 - √144 / 6 = -12/6 = -2
HP {2 , -2}
2.
4x² + 8 = 6x
4x² - 6x + 8 = 0
a = 4
b = -6
c = 8
X1,2 = -b ± √b² - 4ac / 2a
X1,2 = 6 ± √(-6)² - 4.4.8 / 2.4
X1,2 = 6 ± √36 - 128 / 8
X1,2 = 6 ± √-92 / 8
X1,2 = 6 ± 2√-23 / 8
X1,2 = 3 ± √-23 / 4
X1 = 3+√-23 / 4
X2 = 3-√-23 / 4
HP {(3+√-23 /4) , (3-√-23 /4)}
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