Tentukan invers dari 3x-5/2x+7 ; x ≠ 7/2

Ingat:
y= ax+b/cx+d
y^-1= -dx+b/cx-a

f(x)=3x-5/2x+7
f(x)^-1= -7x-5/2x-3

(3x - 5)/(2x + 7) = y
3x - 5 = 2xy + 7y
3x - 2xy = 7y + 5
x(3 - 2y) = 7y + 5
x = (7y + 5)/(3 - 2y)
f^-1(x) = (7x + 5)/(3 - 2x) ; x ≠ 3/2