Tentukan f^-1(3) dari f(x)=2x+5/4x-10 ; x ≠ 5/2
Matematika
lani07
Pertanyaan
Tentukan f^-1(3) dari f(x)=2x+5/4x-10 ; x ≠ 5/2
1 Jawaban
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1. Jawaban AndreJS
f(x) = (2x+5)/(4x-10)
→ y = (2x+5)/(4x-10)
y (4x-10) = 2x+5
4xy-10y = 2x-5
4xy-2x = 10y-5
x (4y-2) = 10y-5
x = (10y-5)/(4y-2)
→ f^(-1) (x) = (10x-5)/(4x-2)
Jadi,
f^(-1) (3) = (10.3-5)/(4.3-2)
f^(-1) (3) = (30-5)/(12-2)
f^(-1) (3) = (25)/(10)
f^(-1) (3) = 2,5