jika f(x) = 2x-3 dan g(x) = 1/3x+1 untuk x ≠ -1/3 maka (g•f)–¹(x-1/2)...

gof(x) = 1 / {3(2x - 3)+1}
gof(x) = 1 / {6x - 8}
y = 1 / 6x - 8
y(6x - 8) = 1
6xy - 8y = 1
6xy = 8y + 1
x = (8y + 1) / 6y
(gof)-¹(x) = (8x + 1) / 6x
(gof)-¹((x-1)/2) = (8(x-1 / 2) + 1) / 6(x-1 / 2)
= (4x - 4 + 1) / (3x - 3)
= (4x - 3) / (3x - 3)