Hitunglah konsentrasi ion Ag+ didalam larutan jenuh AgCrO4 jika diketahui Ksp Ag2CrO4 = 1,1 × 10^-12

Ksp Ag2CrO4 → 2Ag+ + CrO4^2-
1,1*10^-12 = (2s)²*s
1,1*10^-12 = 4s^3
0,275*10^-12 = s^3
0,65*10^-4 = s
6,5*10^-5 = s

Konsentrasi Ag = 4s²
= 4(6,5*10^-5)²
= 169*10^-10
= 1,69*10^-8