Ini gimana caranya?

x² - 8x + 6 = 0
[tex] x_{1}+ x_{2} = 8 \\ x_{1}. x_{2} =6 [/tex]

persamaan baru akarnya tiga lebihnya dari akar2 yang lama.
α = [tex] x_{1} + 3[/tex], β = [tex] x_{2} [/tex] + 3

[tex] \alpha + \beta = x_{1} + 3 + x_{2} + 3 = x_{1} + x_{2} + 6 = 14 \\ \alpha . \beta =(x_{1} + 3) . ( x_{2} +3) =( x_{1} . x_{2} ) + 3( x_{1} + x_{2}) + 9 = 6 + 3.8 + 9 = 39[/tex]

y = x² - (α + β)x + α.β
y = x² - 14x + 39  ............... (A)