Penyelesaian sistem persamaan 1/x-3/y=3 2/x+6/y=2 adalah x1 dan y1. Nilai dari 2x1 - y1 =

misal p = 1/x
q = 1/y

p - 3q = 3
2p + 6q = 2 |÷2| ---> p + 2q = 1
eliminasi
p - 3q = 3
p + 2q = 1
--------------
-5q = 2
q = 2/-5 = -2/5
p - 3(-2/5) = 3
p + 6/5 = 3
p = 3 - 6/5
p = 15/5 - 6/5 = 9/5

p = 1/x
9/5 = 1/x
x = 5/9

q = 1/y
-2/5 = 1/y
y = -5/2

2x - y = 2(5/9) - (-5/2)
= 20/18 + 45/18
= 65/18