bantu jawab ini, logaritma dengan pembahasan

{ (9log4 . 2log27 + 3log81)/(2log64 - 2log8) }^2
= { (3^2log2^2 . 2log3^3 + 3log3^4) / (2log2^6 - 2log2^3) }^2
= { (2/2 . 3log2 . 3 . 2log3 + 4 . 3log3) / (6 . 2log2 - 3 . 2log2) }^2
= { (1 . 3 . 3log2 . 2log3 + 4 . 1) / (6 . 1 - 3 . 1) }^2
= { (3 + 4) / (6 - 3) }^2
= (7/3)^2
= 49/9