Matematika

Pertanyaan

2log1/8-2log32+2log128

2 Jawaban

  • 2log1/8 - 2log32 + 2log128
    2log1 - 2log8 - 2log32 + 2log128
    0 - 3 - 5 + 8 + 0
  • 2log1/8-2log32+2log128

    2log [(1/8)/32] x 128

    2log [( 1/8.32) ×128]

    2log 1/2

    2log (2^-1)

    -1

    Atau

    2log1/8-2log32+2log128

    2log (2^ -3) - 2log 2^5 + 2log 2^7

    -3 x 2log 2 - 5 × 2log 2 + 7x 2log2

    -3× 1 - 5 ×1 + 7× 1

    -3 -5 + 7

    -8+ 7

    -1

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